Question

What is the solution of the differential equation y=px+logp
(A) y=cx+logc
(B) y=xy+logx
(C) y=cx+logp
(D) all of these​

Answer 1

SOLUTION

TO CHOOSE THE CORRECT OPTION

The solution of the differential equation

y = px + logp

(A) y = cx + logc

(B) y = xy + logx

(C) y = cx + logp

(D) all of these

EVALUATION

Here the given differential equation is

y = px + logp

Which is of the form y = px + f(p)

So this is a Clairaut's equation

So the required solution is obtained replacing p by c

Hence the required solution is

y = cx + log c

FINAL ANSWER

Hence the correct option is (A) y = cx + logc

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