Question

what is the solution of the equations 8x+3y=5 and 3x-2y=5? *

(1,1)

(-1,-1)

(-1,1)

(1,-1)​

Answer 1

Answer:

The solution of the given linear equations is ( x, y ) = ( 1, - 1 ).

Option 4) ( 1, - 1 )

Step-by-step-explanation:

The given linear equations are

8x + 3y = 5 - - - ( 1 ) &

3x - 2y = 5 - - - ( 2 )

As RHS of both equations is equal, equating LHS of both equations, we get,

8x + 3y = 3x - 2y

⇒ 8x - 3x = - 2y - 3y

⇒ 5x = - 5y

⇒ x = - 5y ÷ 5

⇒ x = - y

By substituting x = - y in equation ( 1 ), we get,

8x + 3y = 5 - - - ( 1 )

⇒ 8 ( - y ) + 3y = 5

⇒ - 8y + 3y = 5

⇒ - 5y = 5

⇒ y = - 5 ÷ 5

⇒ y = - 1

Now,

x = - y

⇒ x = - ( - 1 )

⇒ x = 1

∴ The solution of the given linear equations is ( x, y ) = ( 1, - 1 ).