Question

What is the solution of this 4b²+28bc+49c²

Answer 1

Answer:

this is of the for (a+b)²=a² +2ab+b²

4b²+28bc+49c²= (2b+7c)²

hope it helps you....

Answer 2

Answer:

$(2b + 7c) {}^{2}$

Step-by-step explanation:

Solve the equation:

$4b {}^{2} + 28bc + 49c {}^{2}$

Factor in the form of:

${a}^{2} + 2ab + {b}^{2}$

$(2b) {}^{2} + 2 \times (2b) \times (7c) + (7c) {}^{2}$

$(2b + 7c) {}^{2}$

Hints:

$(a + b) { }^{2} = a { }^{2} + 2ab + {b}^{2}$