Question

What is the solution (q, r) to this system of linear equations?

12q + 3r = 15

–4q – 4r = –44 A–18, 29)
B(–2, 13)
C(8, –1)
D(15, –44)

Answer 1

12q+3r=15

-4q-4r=-44

12q+3r=15

-12q-12r=-132

-9r=-117

r=13

12q+39=15

12q=15-39

q=-2

r=13

q=-2

(-2,13)