Question

What is the solution to the following system of equations? x − 4y = 6 2x + 2y = 12 (0, 10) (10, 0) (6, 0) (0, 6)

Answer 1

$x - 4y = 6 \\ 2x + 2y = 12 \\ put \: x = 0 \\ \: in \: 1 \: equation \\ 0 - 4y = 6 \\ - 4y = 6 \\ y = \frac{ - 6}{ 4} \\ (0 \: 10) \: is \: not \: a \: solution \\ \: put \: x = 10 \\ 10 - 4y = 6 \\ - 4y = - 4 \\ y = 1 \\ (10 \: 0)is \: not \: a \: solution \\ put \: x = 6 \\ 6 - 4y = 6 \\ - 4y = 0 \\ y = \frac{0}{ - 4} \\ \: y = 0 \\ put \: x = 6 \: in \: 2 \: equation \\ 2 \times 6 + 2y = 12 \\ 12 + 2y = 12 \\ 2y = 0 \\ y = \frac{0}{2} \\ then(6 \: 0) \: is \: soution$