Math, asked by amansinghjatt8331, 10 months ago

What is the solution to the Initial Value Problem (IVP) y''=2e−x with the IVs y(0)=1,y'(0)=0?

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Answered by sks2971996

0

we need to integrate the equation 2 times and find the constants using the above given conditions. Hope this will help you.

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