Question

what is the solutions of quadratic equation 2x^2-7x+6=0​

Answer 1

Step-by-step explanation:

2x²-7x+6=0

b +- roota D/4

Answer 2

3-x = 2*x^2-8*x+9 \ \\ -2x^2 +7x -6 =0 \ \\ 2x^2 -7x +6 =0 \ \\ \ \\ a=2; b=-7; c=6 \ \\ D = b^2 - 4ac = 7^2 - 4\cdot 2 \cdot 6 = 1 \ \\ D>0 \ \\ \ \\ x_{1,2} = \dfrac{ -b \pm \sqrt{ D } }{ 2a } = \dfrac{ 7 \pm \sqrt{ 1 } }{ 4 } \ \\ x_{1,2} = \dfrac{ 7 \pm 1 }{ 4 } \ \\ x_{1,2} = 1.75 \pm 0.25 \ \\ x_{1} = 2 \ \\ x_{2} = 1.5 \ \\ \ \\ \text{ Factored form of the equation: } \ \\ 2 (x -2) (x -1.5) = 0 \ \\3−x=2∗x

2

−8∗x+9

−2x

2

+7x−6=0

2x

2

−7x+6=0

a=2;b=−7;c=6

D=b

2

−4ac=7

2

−4⋅2⋅6=1

D>0

x

1,2

=

2a

−b±

D

=

4

7±

1

x

1,2

=

4

7±1

x

1,2

=1.75±0.25

x

1

=2

x

2

=1.5

Factored form of the equation:

2(x−2)(x−1.5)=0