Question

What is the specific heat capacity of iron if it takes 125 J of heat to raise 111 grams by 2.5 degrees Celsius?

Answer 1

Answer:

C = 450.45 J /Kg °C

Explanation:

We have a formula,

Q = mC∆T

where we take Q in joules, m in Kgs and ∆T in °C.

1. Now first of all, we will need to change m in kgs.

We know that,

1 kg = 1000g

1kg

111 g × ---------- = 0.111 kg

1000g

• Now, we will set the formula,

Q = mc∆T

------ --------- (Dividing m∆T on both sides)

m∆T m∆T

==> Q

C = --------

m∆T

now, putting the values,

125 J

C = ----------------------------

0.111 Kg × 2.5 °C

C = 450.45 J /Kg °C

which is the required answer.