Question

what is the specific heat capacity of iron if it takes 259J of heat to raise 111 grams by 5 degree Celsius?​

Answer 1

Answer:

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Answer 2

Answer:

In this problem the change in temperature must be determined by taking the final temperature (Tf) minus the initial temperature (Ti).

6Δ T = Tf - Ti

Δ T = 28.5°C – 10°C

Δ T = 18.5°C

Continue by solving the equation for specific heat capacity.

S = q\ m×∆T

S= 2500 J \ 150 g × 18.5° C

S = 0.9 J \ g° C