Question

What is the specific heat capacity of silver metal if 55.00 g of the metal absorbs 47.3J of heat and the temperature rises 15.0°C?

​

Answer 1

Answer:

The equation used to solve for specific heat capacity is this:

q

=

s

⋅

m

⋅

Δ

T

where q heat absorbed or lost, s is the specific heat capacity, m is the mass, and

Δ

T

is the change in temperature

final temperature

−

initial temperature

From what the problem gave us, we can plug in the numbers:

47.3

=

s

⋅

55.00

⋅

15.0

Simplify:

47.3

=

s

⋅

825

Divide by 825 on both sides:

0.0573

=

s

The units of

s

will be in

cal

g

⋅

C

for this problem, so

s

=

0.0573

cal

g

⋅

C

.

.

. mark as brainless

Answer 2

C

it's only for the points