What is the specific heat of a substance that absorbs 2500 joules of heat when a sample of 100 g of the substance increases in temperature from 10 °C to 70°C?
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Answer:
specific heat=416.6
Explanation:
heat added= mass of the substance*specific heat*change in temperature
2500=0.1*c*60 (100g=0.1kg; chnge in temp=60)
c=416.6
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