Question

What is the specific heat of a substance that absorbs 2500 joules of heat when a sample
of 10 kg of the substance increases in temperature from 10.0ºC to 70.0ºC

Answer 1

$\bold{SPECIFIC \: HEAT \: CAPACITY }$

Its the amount of heat energy required to raise the temperature of per unit area of the body by one degree Celsius.

S. I unit of specific heat capacity is joule per kilogram per kelvin.

$\boxed{SPECIFIC \: HEAT \: CAPACITY =\frac{ amount \: of \: heat \: energy \: supplied }{mass \times change \: in \: temperature }}$

$\boxed{SPECIFIC \: HEAT \: CAPACITY =\frac{ Q}{m \times \Delta t}}$

Given,

mass m = 10 Kg

heat energy Q = 2500 joules

change in temperature Δt = 10 .0 - 70.0

Δt = -60.0

on placing values,

$\boxed{SPECIFIC \: HEAT \: CAPACITY =\frac{Q}{m \times \Delta t}}$

${SPECIFIC \: HEAT \: CAPACITY =\frac{ 2500}{10 \times 60 }}$

$\boxed{SPECIFIC \: HEAT \: CAPACITY = 4.166 J {kg}^{-1} {C}^{-1}}$