Question

What is the specific heat of the material if we require 510 calories to raise the temperature of 170 gm of material from 50°C to 80°C? ​

Answer 1

Explanation:

The key to this problem lies in the value of the specific heat of iron.

c

iron

=

0.108 cal

g

−

1

∘

C

−

1

This tells you that in order to increase the temperature of one unit of mass of iron, i.e. of

1 g

of iron, by one unit of temperature, i.e. by

1

∘

C

, you need to provide it with

0.108 cal

.

Now, you can use the specific heat of iron to figure out the amount of heat needed to increase the temperature of

35.0 g

of iron

35.0

g

⋅

0.108 cal

1

g

⋅

1

∘

C

=

3.78 cal

∘

C

−

1

This tells you that in order to increase the temperature of

35.0 g

of iron by

1

∘

C

, you need to provide it with

3.78 cal

of heat.

In your case, the temperature of the iron must increase byIn your case, the temperature of the iron must increase by

35

∘

C

−

25

∘

C

=

10

∘

C

which means that you will need

10

∘

C

⋅

3.78 cal

1

∘

C

=

37.8 cal

Now, you should round the answer to one significant figure, the number of sig figs you have for the change in temperature, i.e. for

10

∘

C

, but I'll leave it rounded to two sig figs

heat needed = 38 cal

−−−−−−−−−−−−−−−−−−

Answer 2

Answer:

0.1

Explanation:

0.1

0.1

0.1

0.1

0.1 right answer