Question

What is the speed of an apple dropped from a tree after 1.5 second? What distance cover during this time? Take g=10ms (AS) ​

Answer 1

V = u + at

= 0 + (9.8 m/s² × 1.5 s)

= 14.7 m/s

Speed after 1.5 seconds is 14.7 m/s

S = ut + 0.5at²

= 0 + (0.5 × 9.8 m/s² × (1.5 s)²)

= 11.025 m

Distance travelled during this time is 11.025 m.

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Answer 2

Explanation:

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