What is the speed of an apple dropped from a tree after 1.5 seconds?what distance will it cover during this time?take g=10m/s
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v = u + at
= 0 + (9.8 m/s² × 1.5 s)
= 14.7 m/s
Speed after 1.5 seconds is 14.7 m/s
S = ut + 0.5at²
= 0 + (0.5 × 9.8 m/s² × (1.5 s)²)
= 11.025 m
Distance travelled during this time is 11.025 m
= 0 + (9.8 m/s² × 1.5 s)
= 14.7 m/s
Speed after 1.5 seconds is 14.7 m/s
S = ut + 0.5at²
= 0 + (0.5 × 9.8 m/s² × (1.5 s)²)
= 11.025 m
Distance travelled during this time is 11.025 m
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