Question

What is the speed of an apple dropped from a tree after 1.5 second? What distance
will it cover during this time? Take g=10m/s2 (AS)
plz help me with this​

Answer 1

Answer:

u=0,t=1.5s

v=gt=10×1.5

v=15m/s

s=distance =

2

1

gt

2

=

2

1

×10×

4

9

=

4

45

s=11.25m

Explanation:

plz follow me

like your dp

Answer 2

Answer:

v= u±at

u, Initial velocity of apple=0

a, acceleration due to gravity=10 m/s²

t, time = 1.5 second

v, speed of apple=?

v=0±10×1.5=15

>Speed after 1.5 sec =15m/s

Distance covered by apple:-

s=ut±1/2at²

u=0; t=1.5sec ;a=10m/s²

s=0×1.5±1/2×10×(1.5)²=0±1/2 ×10×2.25=11.25

Distance covered by the apple=11.25m

╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬