Question

What is the speed of light in diamond if the refractive index of diamond is 2.4 and velocity of light in vacuum is 3×10

Answer 1

Given that ,

• Refractive index of diamond (n) = 2.4
• Speed of light in vacuum (C) = 3 × (10)^8 m/s

We know that , the refractive index of medium is given by

$\large \sf \fbox{Refractive \: index \: (n) = \frac{Speed \: of \: light \: in \: vacuum }{Speed \: of \: light \: in \: medium } }$

Thus ,

$\sf \mapsto 2.4 = \frac{3 \times {(10)}^{8} }{Speed \: of \: light \: in \: diamond} \\ \\ \sf \mapsto Speed \: of \: light \: in \: diamond = 1.25 \times {(10)}^{8}$

$\therefore \sf \underline{The \: speed \: of \: light \: in \: diamond \: is </p><p> \: 1.25 \times {(10)}^{8} \: m/s }$