Question

What is the speed of proton having de Broglie wavelength of 0.08Å?

(Given: m = 1.67x10-27

kg, h=6.63x10-34 Js)​

Answer 1

Speed, $v=4.96\times 10^4\ m/s$

Explanation:

We have,

De Broglie wavelength of a proton is $\lambda=0.08\ A=0.08\times 10^{-10}\ m$

It is required to find the speed of the proton.

The De-Broglie  wavelength in terms of speed of proton is given by :

$\lambda=\dfrac{h}{mv}\\\\v=\dfrac{h}{m\lambda}\\\\v=\dfrac{6.63\times 10^{-34}}{1.67\times 10^{-27}\times 0.08\times 10^{-10}}\\\\v=4.96\times 10^4\ m/s$

So, the speed of the proton is $4.96\times 10^4\ m/s$.

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De-Broglie wavelength

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