What is the speed of the particle after 2 seconds if it has an acceleration of 2i+3j m/s 2 and an initial velocity of 4i+3j m/s
Answers
Answered by
0
Explanation:
Initial velocity of particle
u
= 3
i
^
+4
j
^
Acceleration
a
= 4
i
^
−3
j
^
Final velocity after 1 second
v
=
u
+
a
t
where t=1 s
⟹
v
= (3
i
^
+4
j
^
)+ (4
i
^
−3
j
^
)×1= 7
i
^
+
j
^
Speed after 1 second ∣
v
∣=
7
2
+1
=
50
m/s
Answered by
3
Answer:
4i+2m/s
hope this may help you!!!
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