what is the sq root of -1
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the square root of (-1) is "i" iota..
heythatsme:
it is i(aota)
I meant (-1)
https://www.google.co.in/search?q=square+root+of+-1&oq=square+root+of+-1&aqs=chrome..69i57j6.7408j0j7&sourceid=chrome&ie=UTF-8
Actually it is undefined but for the sake of simplicity and to solve Complex functions in Complex plane we need to define the square root of -1 as 'i' : iota.
Yaa....I know...
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thanks
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