Question

What is the square of the binomial (8-1x)?
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Answer 1

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${(8 - 1x)}^{2} \\ {(8)}^{2} + {(1x)}^{2} - 2 \times 8 \times 1x \\ 64 + {x}^{2} - 16x \\ = {x}^{2} - 16x + 64$

Answer 2

Answer:

Step-by-step explanation:

(8 - x)^2 = (-x + 8)^2

(-x + 8)^2 = (-x + 8)(-x + 8)

= − ( − + 8 )  +  8 ( − + 8 )

= x^2 - 16x + 64