Question

what is the square of
x^3 - 1/x^3​

Answer 1

(x^3- 1/x^3)^2

As we know the identity

(a-b)^2= a^2+b^2-2ab

So ,

(x^3- 1/x^3)^2

=(x^3)^2 + (1/x^3)^2 -2×(x)^3×(1/x^3)

=x^6+(1/x^6)-2

Answer 2

(x^3- 1/x^3)^2

As we know the identity

(a-b)^2= a^2+b^2-2ab

So , applying these identity here we get

(x^3- 1/x^3)^2

=(x^3)^2 + (1/x^3)^2 -2×(x)^3×(1/x^3)

=(x^3)^2 + (1/x^3)^2 -2×(x)

=x^6+(1/x^6)-2.

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