What is the square root of 0.0081? Find it using the Long Division method.
Answers
Answered by
3
Step-by-step explanation:
Probably you want the square root of 0.0081 i.e. your question is:
√0.0081 = ?
Square root of a number is a number that on multiplying by itself once gives the number of which it is the square root.
$$\begin{lgathered}= \sqrt{ \frac{81}{10000} } \\ = \sqrt{ \frac{9 \times 9}{100 \times 100} } \\ = \frac{9}{100} \\ = 0.09\end{lgathered}$$
Hence, the required answer is 0.09.
√0.0081 = 0.09
Answered by
14
square - root of 0.0081
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![<br />\begin{array}{r|c|r}<br />0.&\overline{0.} \: \overline{00} \: \overline{81} &0.09 \\ <br />\cline{3-3}<br />+0&-0 \: \: \Downarrow \: \qquad & \: \\ <br />\cline{1-2}0.0& \quad 00 \: \: \: \: \: & \: \\ <br />+ 0& \quad - 00 \quad \: \: \: \: & \: \\ <br />\cline{1-2}09& \: \: \quad 00 \: \: 81& \: \\<br />+9& \qquad - 81& \: \\ <br />\cline{1-2} \: & \quad 0 \quad & \: <br />\end{array}<br /> <br />\begin{array}{r|c|r}<br />0.&\overline{0.} \: \overline{00} \: \overline{81} &0.09 \\ <br />\cline{3-3}<br />+0&-0 \: \: \Downarrow \: \qquad & \: \\ <br />\cline{1-2}0.0& \quad 00 \: \: \: \: \: & \: \\ <br />+ 0& \quad - 00 \quad \: \: \: \: & \: \\ <br />\cline{1-2}09& \: \: \quad 00 \: \: 81& \: \\<br />+9& \qquad - 81& \: \\ <br />\cline{1-2} \: & \quad 0 \quad & \: <br />\end{array}<br />](https://tex.z-dn.net/?f=%3Cbr+%2F%3E%5Cbegin%7Barray%7D%7Br%7Cc%7Cr%7D%3Cbr+%2F%3E0.%26amp%3B%5Coverline%7B0.%7D+%5C%3A+%5Coverline%7B00%7D+%5C%3A+%5Coverline%7B81%7D+%26amp%3B0.09+%5C%5C+%3Cbr+%2F%3E%5Ccline%7B3-3%7D%3Cbr+%2F%3E%2B0%26amp%3B-0+%5C%3A+%5C%3A+%5CDownarrow+%5C%3A+%5Cqquad+%26amp%3B+%5C%3A+%5C%5C+%3Cbr+%2F%3E%5Ccline%7B1-2%7D0.0%26amp%3B+%5Cquad+00+%5C%3A+%5C%3A+%5C%3A+%5C%3A+%5C%3A+%26amp%3B+%5C%3A+%5C%5C+%3Cbr+%2F%3E%2B+0%26amp%3B+%5Cquad+-+00+%5Cquad+%5C%3A+%5C%3A+%5C%3A+%5C%3A+%26amp%3B+%5C%3A+%5C%5C+%3Cbr+%2F%3E%5Ccline%7B1-2%7D09%26amp%3B+%5C%3A+%5C%3A+%5Cquad+00+%5C%3A+%5C%3A+81%26amp%3B+%5C%3A+%5C%5C%3Cbr+%2F%3E%2B9%26amp%3B+%5Cqquad+-+81%26amp%3B+%5C%3A+%5C%5C+%3Cbr+%2F%3E%5Ccline%7B1-2%7D+%5C%3A+%26amp%3B+%5Cquad+0+%5Cquad+%26amp%3B+%5C%3A+%3Cbr+%2F%3E%5Cend%7Barray%7D%3Cbr+%2F%3E)
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Hence,
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Hence,
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