What is the square root of 16 +6√7 is
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Answer:
√(16 +6√7) = 3 + √7
Step-by-step explanation:
Let say square root of 16 +6√7 is a + b√c
=> a + b√c = √(16 +6√7)
Squaring both sides
=> a² + b²c + 2ab√c = 16 +6√7
Comparing
2ab√c = 6√7
=> c = 7
=> 2ab = 6
=> ab = 3
=> b = 3/a
a² + b²c = 16
=> a² + 7b² = 16
=> a² + 7(3/a)² = 16
=> a⁴ - 16a² + 63 = 0
=> a⁴ - 7a² - 9a² + 63 = 0
=> (a² - 7)(a² - 9) = 0
=> a = √7 a = 3
=> b = 3/√7 b = 1
using a = 3 & b = 1
a + b√c = 3 + 1√7 = 3 + √7
using a = √7 & b = 3/√7
or √7 + (3/√7)√7 = √7 + 3 = 3 + √7
Hence √(16 +6√7) = 3 + √7
another method
16 + 6√7
= 7 + 9 + 6√7
= 7 + 3√7 + 3√7 + 9
= √7 (√7 + 3) + 3(√7 + 3)
= (√7 + 3)(√7 + 3)
=(√7 + 3)²
= (3 + √7)²
=> √(16 +6√7) = 3 + √7
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