Math, asked by lohiapalak12, 10 months ago

What is the standard deviation of the number of recoveries among 48 patients when the
probability of recovering is 0.75?
(a) 36.
(b) 81.
(c) 9.
(d) 3.​

Answers

Answered by RvChaudharY50
5

Question :- What is the standard deviation of the number of recoveries among 48 patients when the probability of recovering is 0.75 ?

(a) 36.

(b) 81.

(c) 9.

(d) 3.

Solution :-

given that,

→ Probability of recovering = P = 0.75

→ Total patients = n = 48 .

This is a binomial distribution.

we know that, . The variance of a binomial distribution is :- n * P * ( 1 - P ).

So,

Putting values we get,

→ variance = n * P * ( 1 - P )

→ variance = 48 * (0.75) * (1 - 0.75)

→ variance = 48 * (75/100) * (25/100)

→ variance = 48 * (3/4) * (1/4)

→ variance = (48 * 3) / 16

→ variance = 3 * 3

→ variance = 3².

Now, we know that,

→ Standard deviation = √(variance)

Therefore,

Standard deviation = √(3²)

→ Standard deviation = 3 . (Ans.) (Option D).

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