What is the standard deviation of the number of recoveries among 48 patients when the
probability of recovering is 0.75?
(a) 36.
(b) 81.
(c) 9.
(d) 3.
Answers
Question :- What is the standard deviation of the number of recoveries among 48 patients when the probability of recovering is 0.75 ?
(a) 36.
(b) 81.
(c) 9.
(d) 3.
Solution :-
given that,
→ Probability of recovering = P = 0.75
→ Total patients = n = 48 .
This is a binomial distribution.
we know that, . The variance of a binomial distribution is :- n * P * ( 1 - P ).
So,
Putting values we get,
→ variance = n * P * ( 1 - P )
→ variance = 48 * (0.75) * (1 - 0.75)
→ variance = 48 * (75/100) * (25/100)
→ variance = 48 * (3/4) * (1/4)
→ variance = (48 * 3) / 16
→ variance = 3 * 3
→ variance = 3².
Now, we know that,
→ Standard deviation = √(variance)
Therefore,
→ Standard deviation = √(3²)
→ Standard deviation = 3 . (Ans.) (Option D).
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