Question

What is the standard form equation for the parabola y=(x-4)(x-8)?

Answer 1

x^2-12x+32 is the required standard quadratic equation....

Answer 2

Answer:

y+4=(x−6)2.

Explanation:

Given that, y=(x−4)(x−8)=x2−12x+32

⇒y−32=x2−12x

Completing the square on R.H.S.,

y−32+36=x2−12x+36=(x−6)2

∴y+4=(x−6)2.