Question

What is the standard form of the equation of the circle x2 -4x + y2 + 6y - 12 = 0?

Answer 1

Answer:

Step-by-step explanation:

(x^2 - 4x + 4) + (y^2 + 6y + 9) = 25

(x - 2)^2 + (y + 3)^2 = 5^2

Circle with center at (2 , - 3) and radius 5