Question

What is the strain in a wire cable of
original length 50m whose length
increases by 2.5cm when a load is lifted? ans- 5*
${10}^{4}$


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Answer 1

To find:

What is the strain in a wire cable of original length 50m whose length increases by 2.5cm when a load is lifted?

Calculation:

First of all , what is STRAIN ?

• Strain is a dimensionless quantity representing the fraction of change in dimension over the original dimension of an object.

• Strain = ∆L/L

• Being dimensionless, strain doesn't have any unit.

$\sf\therefore \: strain = \dfrac{\Delta L}{ L}$

$\sf\implies \: strain = \dfrac{2.5 \: cm}{ 50 \: m}$

$\sf\implies \: strain = \dfrac{2.5 \times {10}^{ - 2} \: m }{ 50 \: m}$

$\sf\implies \: strain = \dfrac{25 \times {10}^{ - 4} }{ 5 }$

$\sf\implies \: strain = 5 \times {10}^{ - 4}$

So, strain of wire is 5 × 10^(-4).