what is the structure of Cr05. how can we find its oxidation state
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Answered by
8
Hey dear here is the answer
+ 6
This cannot be true as maximum O. N. of Cr cannot be more than + 6. Since Cr has only five electrons in 3d orbitals and one electron in 4s orbital. This exceptional value is due to the fact that four oxygen atoms in CrO5are in peroxide linkage. The chemical structure of CrO5 is.
Therefore, the evaluation of o.n. of Cr should be made as follows
x + 1 × (– 2) + 4 (–1) = 0
(for Cr) (for O) (for O–O)
or x – 2 – 4 = 0 or x = + 6.
HOPE ITS HELP YOU
+ 6
This cannot be true as maximum O. N. of Cr cannot be more than + 6. Since Cr has only five electrons in 3d orbitals and one electron in 4s orbital. This exceptional value is due to the fact that four oxygen atoms in CrO5are in peroxide linkage. The chemical structure of CrO5 is.
Therefore, the evaluation of o.n. of Cr should be made as follows
x + 1 × (– 2) + 4 (–1) = 0
(for Cr) (for O) (for O–O)
or x – 2 – 4 = 0 or x = + 6.
HOPE ITS HELP YOU
Answered by
17
the structure of Cr05 is known as butterfly structure.
as u can see the ketone group oxygen has oxidation stae -2 and all the other bonded oxygen atoms have oxidation state -1 . so we can find out oxdation state
-2+4(-1)+x=0
x=+6
as u can see the ketone group oxygen has oxidation stae -2 and all the other bonded oxygen atoms have oxidation state -1 . so we can find out oxdation state
-2+4(-1)+x=0
x=+6
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