Math, asked by nehaabrahamjoji, 7 months ago

what is the sum and product of zeroes of 2(x²-1) + 3x - 9???

Answers

Answered by moshnetic
1

Answer:

sum of zeroes = - b / a = - 3 / 2

product of zeroes  = c / a = - 11 / 2

Step-by-step explanation:

Solving brackets:

2(x²-1) + 3x - 9 = 2x² - 2 + 3x - 9

= 2x² + 3x - 11

here, a = 2   ,  b = 3   and  c = - 11

sum of zeroes = - b / a = - 3 / 2

product of zeroes  = c / a = - 11 / 2

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