what is the sum and product of zeroes of 2(x²-1) + 3x - 9???
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Answer:
sum of zeroes = - b / a = - 3 / 2
product of zeroes = c / a = - 11 / 2
Step-by-step explanation:
Solving brackets:
2(x²-1) + 3x - 9 = 2x² - 2 + 3x - 9
= 2x² + 3x - 11
here, a = 2 , b = 3 and c = - 11
sum of zeroes = - b / a = - 3 / 2
product of zeroes = c / a = - 11 / 2
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