Question

What is the sum of 1+ 3 + 5 + ... + 49?​

Answer 1

Answer:

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Step-by-step explanation:

$\large\bold\red{Question}$

What is the sum for 1+3+…+47+49?

$\large\bold\blue{Answer}$

According to Arithmetic progression, We know that last term of an AP is

l = a+(n-1)d

Here l=49, a=1, d=2, n=?.

Then

49= 1+(n-1)²

49–1=(n-1)²

48=(n-1)²

n-1=48/2

n-1=24

n=24+1

n=25

that is total no of terms is this AP.

Sum of AP:

=n(a+l)/2

=25(1+49)/2

=25×50/2

=25×25

=625

Answer 2

Answer:

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