what is the sum of (3y8-4y6+5y4)÷y4
Jaanki:
3y^4 - 4y^2 + 5 ?
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Answered by
7
(3y8-4y6+5y4)÷4y
=(24y-24y+20y)÷4y
( after cancelling)
20y÷4y = 5
.
.
hope it is correct.
=(24y-24y+20y)÷4y
( after cancelling)
20y÷4y = 5
.
.
hope it is correct.
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Answered by
6
Answer:
5 is the final answer
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