Question

What is the sum of 4 consecutive powers of iota
(i^1)+(i^2)+(i^3)+(i^4)=?

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Answer 1

Answer:

Sum of four consecutive powers of i (iota) is zero. i.e., i^n+i^n+1+i^n+2+i^n+3=0, ∀ n∈I.

(i^1)+(i^2)+(i^3)+(i^4)= 0.

✔️Hope it will help you.✔️

Answer 2

Answer:

Answer is 0 (zero) of this question