Question

What is the sum of (8a2 – 5ab + 3b2), (2ab – 6b2 + 3a2) and (b2 + ab – 6a2)?

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Answer 1

Answer:

$Heres your answer</p><p></p><p>8 {a}^{2} - 5ab + 3 {b}^{2} + 2ab - 6 {b}^{2} + 3 {a}^{2} + {b}^{2} + ab - 6 {a}^{2} \\ we \: can \: conclude \\ 8 {a}^{2} + 3 {a}^{2} - 6 {a}^{2} + 3 {b}^{2} - 6 {b}^{2} + {b}^{2} - 5ab + 2ab + ab \\ 11 {a}^{2} - 6 {a}^{2} - 3 {b}^{2} + {b}^{2} - 3ab + ab \\ = 5 {a}^{2} - 2 {b}^{2} - 2ab</p><p></p><p>[tex]5 {a}^{2} - 2 {b}^{2} - 2ab \\ \\ = 5 {a}^{2} - 2b(b + a)</p><p></p><p>Hope it Helps !!$