Question

What is the sum of a 58-term arithmetic sequence where the first term is 6 and the last term is 405?

Answer 1

Answer:

Sum of first 58 terms of the A.P is 11,919

Step-by-step explanation:

Formula used:

The sum of n terms of an A.P a, a+d, a+2d,.... is

$S_n=\frac{n}{2}[a+l]$

Given:

first term, a=6

last term, l=405

Now,

Sum of first 58 terms of the A.P

$=S_{58}$

$=\frac{n}{2}[a+l]$

$=\frac{58}{2}[6+405]$

$=29[411]$

$=11,919$

Answer 2

Answer:

11,919

Step-by-step explanation: