Question

What is the sum of additive inverse and multiplicative inverse of 2

Answer 1

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Additive inverse of 2 = -2
Multiplicative inverse of 2 = 1/2

Their sum =
$- 2 + \frac{1}{2} = \frac{ - 4 + 1}{2} \\ \\ = \frac{ - 3}{2}$
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Answer 2

The sum of additive inverse and multiplicative inverse of 2 is - 3/2

Given :

The number 2

To find :

The sum of additive inverse and multiplicative inverse of 2

Solution :

Step 1 of 3 :

Find additive inverse of 2

Let m is the additive inverse of 2

Then we have ,

$\displaystyle \sf{ m + 2 = 0}$

$\displaystyle \sf{ \implies m = - 2}$

So additive inverse of 2 is - 2

Step 2 of 3 :

Find multiplicative inverse of 2

Let n is the multiplicative inverse of 2

Then we have ,

$\displaystyle \sf{n \times 2 = 1 }$

$\displaystyle \sf{ \implies n = \frac{1}{2} }$

So multiplicative inverse of 2 is 1/2

Step 3 of 3 :

Find sum of additive inverse and multiplicative inverse of 2

Hence the required sum of additive inverse and multiplicative inverse of 2

$\displaystyle \sf{ = - 2 + \frac{1}{2} }$

$\displaystyle \sf{ = \frac{ - 4 + 1}{2} }$

$\displaystyle \sf{ = \frac{ - 3}{2} }$

$\displaystyle \sf{ = - \frac{3}{2} }$

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