Math, asked by ravikarre932, 11 hours ago

what is the sum of all 2digit numbers which leave remainder 3 when divided by 11

Answers

Answered by sanvisharma3500

0

Answer:

All 2 digits numbers which leave a remainder 3 when divided by 11 are 14,25,36,47,58,69,80,91.

Sum = 14+25+36+47+58+69+80+91

This A P whose 1st term is 14 ,last term is 91 and numbers of terms equal to 8

S = (n/2)×(a+l)

S = (8/2)×(14+91)

S = 4×105

S = 420

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