What is the sum of all 4 digit numbers formed using the digits 2, 3,4 and 5 without repetition?
Answers
Answered by
15
93324 is the right answer of this question
Answered by
83
Answer:
the answer is 93324
Step-by-step explanation:
here is the formula for sum of the numbers formed by taking all the given n digits = (sum of all digits) × (n-1)! × (11....n times)
=(2+3+4+5) × (4-1)! × (1111) ⇒n=4 that is why 1111
=(20) × 3! × 1111
=20 × 6 × 1111
= 93324
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