Question

What is the sum of all even integers between 99 to 301?

Answer 1

Answer:

Step-by-step explanation:

Here First term,a=100

Common difference,d=102-100=104-102=.....=2

Last term,l=300

Now we have a relationship among a,d and I

l=a+(n-1)*d

where n is number of terms

300=100+(n-1)*2

200=(n-1)*2

(n-1)=100

n=101

Now we have to find sum of these 101 terms

Sum of n terms of an arithmetic progression is given by Sn

Sn=n*(2*a+(n-1)*d)/2

S101=101*(2*100+(101-1)*2)/2

S101=101*(200+100*2)/2

S101= 101*400/2

S101=20200

Sum of all even integers between 99 and 301 is therefore 20200

Answer 2

Step-by-step explanation:

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