Math, asked by shareennisha2434, 5 months ago

What is the sum of all integer value of n for which n^2+19n+92

Answers

Answered by vivekgakkhar0710
0

Answer:

-19

Step-by-step explanation:

n²+19n+92

here a=1 , b=19 , c=92

It's a quadratic equation so it has maximum two roots.

Let two roots are

 \alpha  \: and \:  \beta  \\ so \: \alpha  +  \beta  =   \frac{ - b}{a} =  \frac{-19}{1 }  = -19

so the sum of all integer value of n= -19

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