What is the sum of all natural numbers between 100 and 400 which are divisible by 13? Solution: answer : option a oops! Wrong answer! First number divisible by 13 between 100 and 400 is 104 and last number is 390 390=104+(n-1) 13 286=(n-1) 13 n=23 sum=?
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the sum of numbers will be 5681 having n =23
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