Question

What is the sum of all natural numbers between 300 ; 500

Answer 1

Answer:

80000

Step-by-step explanation:

a (first term) = 300

d (common difference) = 1

l (last term) =500

n( number of terms) =200

Sum = n/2 (a+l)

=> sum= 200/2 (300 + 500)

=> sum = 100 (800)

=> sum = 80000

Answer 2

Please mark as brainliest

Answer:

A.P: 301, 302...499

as numbers are between 300 and 500.

Step-by-step explanation:

a=301, d=1, l=499=a n

as, a n =a+(n-1)d

499=301+(n-1)

198=n-1

n=199

S n =n/2(a+l)

S n=(199/2)(301+499)

S n=199×800

S n=159,200