what is the sum of all natural numbers from 1 to 100 ?
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Answered by
5
Answer:
5050
Step-by-step explanation:
This is an arithmetic series, for which the formula is:
S = n[2a+(n-1)d]/2
where a is the first term, d is the difference between terms, and n is the number of terms.
For the sum of the first 100 whole numbers:
a = 1, d = 1, and n = 100
Therefore, sub into the formula:
S = 100[2(1)+(100-1)(1)]/2 = 100[101]/2 = 5050
Answered by
0
Sum of the 1 to 100 numbers is
n(n+1)/2
100×(100+1)/2
100 ×101/2
50×101
5050
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