Question

what is the sum of all natural numbers from 1 to 100?(please answer to myquestion​

Answer 1

Answer:

S(n) = n/2(a+l)

where n is term

a is first term

l is last term

100/2(1+100)

=5050

for any doubt what's app no. 9467169711

Answer 2

Answer:

5050

Step-by-step explanation:

Sn=n/2(2a+(n-1)d)

n=100

so,first term a=1

common difference d=3-2=1

so,S100=100/2(2(1)+(100-1)1)

=50(2+99)

=50(101)

=5050