Math, asked by Manavprajapati, 9 months ago

what is the sum of all natural numbers from one to hundred​

Answers

Answered by Puneeth555
4

Answer:

5050

Step-by-step explanation:

o calculate the sum of 1–100 there is a trick

First calculate the sum of 1–10

It is

1+2+3+4+5+6+7+8+9+10 = 55

Similarly the sum of next ten numbers, that is from 11–20

It is

11+12+13+14+15+16+17+18+19+20 = 155

From the above two sums it is clear that the sum of next ten numbers numbers would be 255.

Similarly we would get 355,455,555,655,755,855,955.

Now adding all these sums, that is

55+155+255+355+455+555+655+755+855+955 = 5050.

Edit- The above method is solved without any formulas. But there is a formula for solving this problem.

Sn=n(n+1)/2

The derivation of this formula-

Let Sn=1+2+3+.....+n (equation 1)

By rearrangement

Sn=n+(n−1)+(n−2)+....+1 (equation 2)

By adding equation 1 & 2

2Sn=(n+1)+(2+n−1)+(3+n−2)+.....+(n+1)

2Sn=(n+1)+(n+1)+(n+1)+....+(n+1)

In the above equation n+1 is added n times

Therefore,

2Sn=n(n+1)

Sn=n(n+1)/2

Here n=100

Sn=100∗101/2

=10100/2

=5050

Answered by anupsavaliya28
0

Answer:

5050

Step-by-step explanation:

sum of all natural nos forms an AP

1,2,3,.....100

a=1,d=1. an=100

an=a+(n-1)d

100=1+(n-1)1

n=100

Sn=(n/2)[2a+(n-1)d]

=50(2+99(1))

=50*101

=5050

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