Question

what is the sum of all natural numbers that are less than 120 and divisible by 4​

Answer 1

Step-by-step explanation:

First number divisible by 4 is 4

Last number divisible by 4 is 120

Therefore the total number of terms

an = a + (n - 1 )d

120 = 4 + ( n - 1) 4

n - 1 = 116/4

n - 1 = 29

n = 28

Now sum of 28 terms

= $\frac{n(a + l)}{2}$

= 14 ( 4 + 120)

=1736

Answer 2

Answer:

go away uselesssssdssssssssssssssss

Step-by-step explanation: