What is the sum of all no. From 1 to 100
muskan158:
5050
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Answered by
5
see accourding to A.P
a=1
d=1
sn=[n/2{2a +(n-1)d}]
s100 =[100/2{2x1+(100-1)1}]
s100=[50{2+(99)1}]
s100=50(101)
s100=5050
the sum of all no. from 1to 100 is 5050
a=1
d=1
sn=[n/2{2a +(n-1)d}]
s100 =[100/2{2x1+(100-1)1}]
s100=[50{2+(99)1}]
s100=50(101)
s100=5050
the sum of all no. from 1to 100 is 5050
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4
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