What is the sum of all numbers from 1 to 100
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Solution :-
given numbers are 1, 2, 3, 4, _________ 100 . Since difference between each numbers is same . We can say that they are in AP .
So,
→ First number = a = 1
→ Total terms = n = 100
→ Last term = L = 100
then,
→ Sn = (n/2)[a + L]
→ Sn = (100/2)[1 + 100]
→ Sn = 50 * 101
→ Sn = 5050 (Ans.)
Shortcut :-
→ Sum of first n natural numbers = n(n + 1)/2
given that n = 100,
So,
→ Required sum = {100 * (100 + 1)}/2
→ Required sum = 50 * 101
→ Required sum = 5050 (Ans.)
Hence, the sum of all numbers from 1 to 100 is equal to 5050 .
Learn more :-
write the first 5 odd multiples of 7
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