Question

What is the sum of all numbers from 1 to 500 ?
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Answer 1

Answer:

your answer is 125250

Step-by-step explanation:

step 1 address the formula, input parameters & values.

Input parameters & values:

The number series 1, 2, 3, 4, . . . . , 499, 500.

The first term a = 1

The common difference d = 1

Total number of terms n = 500

step 2 apply the input parameter values in the formula

Sum = n/2 x (a + Tn)

= 500/2 x (1 + 500)

= 250500/2

1 + 2 + 3 + 4 + . . . . + 499 + 500 = 125250

Therefore, 125250 is the sum of positive integers upto 500.

hope it helps you

Answer 2

Given: numbers from 1 to 500.

Here we have to find the sum of all numbers from 1 to 500.

We are using the formula of the Sum of Integers.

Sum of Integers Formula:

$\mathrm{S}=\frac{\mathrm{n}(\mathrm{a}+I)}{2}$

Where, S = sum of the consecutive integers,

n = number of integers,  a = first term,  l = last term.

We have,

$a=1,\\n=500,\\I=500.$

By putting this values in the formula,

we get,

$S=\frac{n(a+I)}{2} \\\\S=\frac{500(1+500)}{2} \\\\S=125250$

So, the sum of all numbers from 1 to 500 is 125250.