What is the sum of all odd integers between 2 and 16
Answers
Answered by
0
Answer:
The odd integers between 2 and 100 which are divisible by 3 are 3, 9, 15, 21, ..., 99.
Here, a=3 and d=6.
an=99
⇒a+(n−1)d=99
⇒3+(n−1)×6=99
⇒6(n−1)=96
⇒n−1=16
⇒n=17
Therefore,
Required sum = 2n(a+l)=217(3+99)=867
Step-by-step explanation:
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Answered by
0
Answer:
63
Step-by-step explanation:
odd integers are 3,5,7,9,11,13,15
sum =n(2a+(n-1)d)
2
{a=3,d=2,n=7}
=7 (2×3+(7-1)2)
2
=7 (6+12)
2
=7 ×18
2
=7×9
=63
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